Class RDD

x.__init__(...) initializes x; see help(type(x)) for signature

Overrides: object.__init__

(inherited documentation)

repr(x)

Overrides: object.__repr__

(inherited documentation)

The SparkContext that this RDD was created on.

Decorators:

• @property

Set this RDD's storage level to persist its values across operations after the first time it is computed. This can only be used to assign a new storage level if the RDD does not have a storage level set yet.

Mark this RDD for checkpointing. It will be saved to a file inside the checkpoint directory set with SparkContext.setCheckpointDir() and all references to its parent RDDs will be removed. This function must be called before any job has been executed on this RDD. It is strongly recommended that this RDD is persisted in memory, otherwise saving it on a file will require recomputation.

Return a new RDD by applying a function to each element of this RDD.

>>> rdd = sc.parallelize(["b", "a", "c"])
>>> sorted(rdd.map(lambda x: (x, 1)).collect())
[('a', 1), ('b', 1), ('c', 1)]

Return a new RDD by first applying a function to all elements of this RDD, and then flattening the results.

>>> rdd = sc.parallelize([2, 3, 4])
>>> sorted(rdd.flatMap(lambda x: range(1, x)).collect())
[1, 1, 1, 2, 2, 3]
>>> sorted(rdd.flatMap(lambda x: [(x, x), (x, x)]).collect())
[(2, 2), (2, 2), (3, 3), (3, 3), (4, 4), (4, 4)]

Return a new RDD by applying a function to each partition of this RDD.

>>> rdd = sc.parallelize([1, 2, 3, 4], 2)
>>> def f(iterator): yield sum(iterator)
>>> rdd.mapPartitions(f).collect()
[3, 7]

Return a new RDD by applying a function to each partition of this RDD, while tracking the index of the original partition.

>>> rdd = sc.parallelize([1, 2, 3, 4], 4)
>>> def f(splitIndex, iterator): yield splitIndex
>>> rdd.mapPartitionsWithIndex(f).sum()
6

Deprecated: use mapPartitionsWithIndex instead.

Return a new RDD by applying a function to each partition of this RDD, while tracking the index of the original partition.

>>> rdd = sc.parallelize([1, 2, 3, 4], 4)
>>> def f(splitIndex, iterator): yield splitIndex
>>> rdd.mapPartitionsWithSplit(f).sum()
6

Returns the number of partitions in RDD

>>> rdd = sc.parallelize([1, 2, 3, 4], 2)
>>> rdd.getNumPartitions()
2

Return a new RDD containing only the elements that satisfy a predicate.

>>> rdd = sc.parallelize([1, 2, 3, 4, 5])
>>> rdd.filter(lambda x: x % 2 == 0).collect()
[2, 4]

Return a new RDD containing the distinct elements in this RDD.

>>> sorted(sc.parallelize([1, 1, 2, 3]).distinct().collect())
[1, 2, 3]

Return a fixed-size sampled subset of this RDD (currently requires numpy).

>>> rdd = sc.parallelize(range(0, 10))
>>> len(rdd.takeSample(True, 20, 1))
20
>>> len(rdd.takeSample(False, 5, 2))
5
>>> len(rdd.takeSample(False, 15, 3))
10

Return the union of this RDD and another one.

>>> rdd = sc.parallelize([1, 1, 2, 3])
>>> rdd.union(rdd).collect()
[1, 1, 2, 3, 1, 1, 2, 3]

Return the intersection of this RDD and another one. The output will not contain any duplicate elements, even if the input RDDs did.

Note that this method performs a shuffle internally.

>>> rdd1 = sc.parallelize([1, 10, 2, 3, 4, 5])
>>> rdd2 = sc.parallelize([1, 6, 2, 3, 7, 8])
>>> rdd1.intersection(rdd2).collect()
[1, 2, 3]

Return the union of this RDD and another one.

>>> rdd = sc.parallelize([1, 1, 2, 3])
>>> (rdd + rdd).collect()
[1, 1, 2, 3, 1, 1, 2, 3]

Sorts this RDD, which is assumed to consist of (key, value) pairs. # noqa

>>> tmp = [('a', 1), ('b', 2), ('1', 3), ('d', 4), ('2', 5)]
>>> sc.parallelize(tmp).sortByKey().first()
('1', 3)
>>> sc.parallelize(tmp).sortByKey(True, 1).collect()
[('1', 3), ('2', 5), ('a', 1), ('b', 2), ('d', 4)]
>>> sc.parallelize(tmp).sortByKey(True, 2).collect()
[('1', 3), ('2', 5), ('a', 1), ('b', 2), ('d', 4)]
>>> tmp2 = [('Mary', 1), ('had', 2), ('a', 3), ('little', 4), ('lamb', 5)]
>>> tmp2.extend([('whose', 6), ('fleece', 7), ('was', 8), ('white', 9)])
>>> sc.parallelize(tmp2).sortByKey(True, 3, keyfunc=lambda k: k.lower()).collect()
[('a', 3), ('fleece', 7), ('had', 2), ('lamb', 5),...('white', 9), ('whose', 6)]

Sorts this RDD by the given keyfunc

>>> tmp = [('a', 1), ('b', 2), ('1', 3), ('d', 4), ('2', 5)]
>>> sc.parallelize(tmp).sortBy(lambda x: x[0]).collect()
[('1', 3), ('2', 5), ('a', 1), ('b', 2), ('d', 4)]
>>> sc.parallelize(tmp).sortBy(lambda x: x[1]).collect()
[('a', 1), ('b', 2), ('1', 3), ('d', 4), ('2', 5)]

Return an RDD created by coalescing all elements within each partition into a list.

>>> rdd = sc.parallelize([1, 2, 3, 4], 2)
>>> sorted(rdd.glom().collect())
[[1, 2], [3, 4]]

Return the Cartesian product of this RDD and another one, that is, the RDD of all pairs of elements (a, b) where a is in self and b is in other.

>>> rdd = sc.parallelize([1, 2])
>>> sorted(rdd.cartesian(rdd).collect())
[(1, 1), (1, 2), (2, 1), (2, 2)]

Return an RDD of grouped items.

>>> rdd = sc.parallelize([1, 1, 2, 3, 5, 8])
>>> result = rdd.groupBy(lambda x: x % 2).collect()
>>> sorted([(x, sorted(y)) for (x, y) in result])
[(0, [2, 8]), (1, [1, 1, 3, 5])]

Return an RDD created by piping elements to a forked external process.

>>> sc.parallelize(['1', '2', '', '3']).pipe('cat').collect()
['1', '2', '', '3']

Applies a function to all elements of this RDD.

>>> def f(x): print x
>>> sc.parallelize([1, 2, 3, 4, 5]).foreach(f)

Applies a function to each partition of this RDD.

>>> def f(iterator):
...      for x in iterator:
...           print x
...      yield None
>>> sc.parallelize([1, 2, 3, 4, 5]).foreachPartition(f)

Reduces the elements of this RDD using the specified commutative and associative binary operator. Currently reduces partitions locally.

>>> from operator import add
>>> sc.parallelize([1, 2, 3, 4, 5]).reduce(add)
15
>>> sc.parallelize((2 for _ in range(10))).map(lambda x: 1).cache().reduce(add)
10

Aggregate the elements of each partition, and then the results for all the partitions, using a given associative function and a neutral "zero value."

The function op(t1, t2) is allowed to modify t1 and return it as its result value to avoid object allocation; however, it should not modify t2.

>>> from operator import add
>>> sc.parallelize([1, 2, 3, 4, 5]).fold(0, add)
15

Aggregate the elements of each partition, and then the results for all the partitions, using a given combine functions and a neutral "zero value."

The functions op(t1, t2) is allowed to modify t1 and return it as its result value to avoid object allocation; however, it should not modify t2.

The first function (seqOp) can return a different result type, U, than the type of this RDD. Thus, we need one operation for merging a T into an U and one operation for merging two U

>>> seqOp = (lambda x, y: (x[0] + y, x[1] + 1))
>>> combOp = (lambda x, y: (x[0] + y[0], x[1] + y[1]))
>>> sc.parallelize([1, 2, 3, 4]).aggregate((0, 0), seqOp, combOp)
(10, 4)
>>> sc.parallelize([]).aggregate((0, 0), seqOp, combOp)
(0, 0)

Find the maximum item in this RDD.

>>> sc.parallelize([1.0, 5.0, 43.0, 10.0]).max()
43.0

Find the minimum item in this RDD.

>>> sc.parallelize([1.0, 5.0, 43.0, 10.0]).min()
1.0

Add up the elements in this RDD.

>>> sc.parallelize([1.0, 2.0, 3.0]).sum()
6.0

Return the number of elements in this RDD.

>>> sc.parallelize([2, 3, 4]).count()
3

Compute a histogram using the provided buckets. The buckets are all open to the right except for the last which is closed. e.g. [1,10,20,50] means the buckets are [1,10) [10,20) [20,50], which means 1<=x<10, 10<=x<20, 20<=x<=50. And on the input of 1 and 50 we would have a histogram of 1,0,1.

If your histogram is evenly spaced (e.g. [0, 10, 20, 30]), this can be switched from an O(log n) inseration to O(1) per element(where n = # buckets).

Buckets must be sorted and not contain any duplicates, must be at least two elements.

If `buckets` is a number, it will generates buckets which are evenly spaced between the minimum and maximum of the RDD. For example, if the min value is 0 and the max is 100, given buckets as 2, the resulting buckets will be [0,50) [50,100]. buckets must be at least 1 If the RDD contains infinity, NaN throws an exception If the elements in RDD do not vary (max == min) always returns a single bucket.

It will return an tuple of buckets and histogram.

>>> rdd = sc.parallelize(range(51))
>>> rdd.histogram(2)
([0, 25, 50], [25, 26])
>>> rdd.histogram([0, 5, 25, 50])
([0, 5, 25, 50], [5, 20, 26])
>>> rdd.histogram([0, 15, 30, 45, 60])  # evenly spaced buckets
([0, 15, 30, 45, 60], [15, 15, 15, 6])
>>> rdd = sc.parallelize(["ab", "ac", "b", "bd", "ef"])
>>> rdd.histogram(("a", "b", "c"))
(('a', 'b', 'c'), [2, 2])

Compute the mean of this RDD's elements.

>>> sc.parallelize([1, 2, 3]).mean()
2.0

Compute the variance of this RDD's elements.

>>> sc.parallelize([1, 2, 3]).variance()
0.666...

Compute the standard deviation of this RDD's elements.

>>> sc.parallelize([1, 2, 3]).stdev()
0.816...

Compute the sample standard deviation of this RDD's elements (which corrects for bias in estimating the standard deviation by dividing by N-1 instead of N).

>>> sc.parallelize([1, 2, 3]).sampleStdev()
1.0

Compute the sample variance of this RDD's elements (which corrects for bias in estimating the variance by dividing by N-1 instead of N).

>>> sc.parallelize([1, 2, 3]).sampleVariance()
1.0

Return the count of each unique value in this RDD as a dictionary of (value, count) pairs.

>>> sorted(sc.parallelize([1, 2, 1, 2, 2], 2).countByValue().items())
[(1, 2), (2, 3)]

Get the top N elements from a RDD.

Note: It returns the list sorted in descending order. >>> sc.parallelize([10, 4, 2, 12, 3]).top(1) [12] >>> sc.parallelize([2, 3, 4, 5, 6], 2).top(2) [6, 5]

Get the N elements from a RDD ordered in ascending order or as specified by the optional key function.

>>> sc.parallelize([10, 1, 2, 9, 3, 4, 5, 6, 7]).takeOrdered(6)
[1, 2, 3, 4, 5, 6]
>>> sc.parallelize([10, 1, 2, 9, 3, 4, 5, 6, 7], 2).takeOrdered(6, key=lambda x: -x)
[10, 9, 7, 6, 5, 4]

Take the first num elements of the RDD.

It works by first scanning one partition, and use the results from that partition to estimate the number of additional partitions needed to satisfy the limit.

Translated from the Scala implementation in RDD#take().

>>> sc.parallelize([2, 3, 4, 5, 6]).cache().take(2)
[2, 3]
>>> sc.parallelize([2, 3, 4, 5, 6]).take(10)
[2, 3, 4, 5, 6]
>>> sc.parallelize(range(100), 100).filter(lambda x: x > 90).take(3)
[91, 92, 93]

Return the first element in this RDD.

>>> sc.parallelize([2, 3, 4]).first()
2

Output a Python RDD of key-value pairs (of form RDD[(K, V)]) to any Hadoop file system, using the new Hadoop OutputFormat API (mapreduce package). Keys/values are converted for output using either user specified converters or, by default, org.apache.spark.api.python.JavaToWritableConverter.

Parameters:

• conf - Hadoop job configuration, passed in as a dict
• keyConverter - (None by default)
• valueConverter - (None by default)

Output a Python RDD of key-value pairs (of form RDD[(K, V)]) to any Hadoop file system, using the new Hadoop OutputFormat API (mapreduce package). Key and value types will be inferred if not specified. Keys and values are converted for output using either user specified converters or org.apache.spark.api.python.JavaToWritableConverter. The conf is applied on top of the base Hadoop conf associated with the SparkContext of this RDD to create a merged Hadoop MapReduce job configuration for saving the data.

Parameters:

• path - path to Hadoop file
• outputFormatClass - fully qualified classname of Hadoop OutputFormat (e.g. "org.apache.hadoop.mapreduce.lib.output.SequenceFileOutputFormat")
• keyClass - fully qualified classname of key Writable class (e.g. "org.apache.hadoop.io.IntWritable", None by default)
• valueClass - fully qualified classname of value Writable class (e.g. "org.apache.hadoop.io.Text", None by default)
• keyConverter - (None by default)
• valueConverter - (None by default)
• conf - Hadoop job configuration, passed in as a dict (None by default)

Output a Python RDD of key-value pairs (of form RDD[(K, V)]) to any Hadoop file system, using the old Hadoop OutputFormat API (mapred package). Keys/values are converted for output using either user specified converters or, by default, org.apache.spark.api.python.JavaToWritableConverter.

Parameters:

• conf - Hadoop job configuration, passed in as a dict
• keyConverter - (None by default)
• valueConverter - (None by default)

Output a Python RDD of key-value pairs (of form RDD[(K, V)]) to any Hadoop file system, using the old Hadoop OutputFormat API (mapred package). Key and value types will be inferred if not specified. Keys and values are converted for output using either user specified converters or org.apache.spark.api.python.JavaToWritableConverter. The conf is applied on top of the base Hadoop conf associated with the SparkContext of this RDD to create a merged Hadoop MapReduce job configuration for saving the data.

Parameters:

• path - path to Hadoop file
• outputFormatClass - fully qualified classname of Hadoop OutputFormat (e.g. "org.apache.hadoop.mapred.SequenceFileOutputFormat")
• keyClass - fully qualified classname of key Writable class (e.g. "org.apache.hadoop.io.IntWritable", None by default)
• valueClass - fully qualified classname of value Writable class (e.g. "org.apache.hadoop.io.Text", None by default)
• keyConverter - (None by default)
• valueConverter - (None by default)
• conf - (None by default)
• compressionCodecClass - (None by default)

Output a Python RDD of key-value pairs (of form RDD[(K, V)]) to any Hadoop file system, using the org.apache.hadoop.io.Writable types that we convert from the RDD's key and value types. The mechanism is as follows:

1. Pyrolite is used to convert pickled Python RDD into RDD of Java objects.
2. Keys and values of this Java RDD are converted to Writables and written out.

Parameters:

• path - path to sequence file
• compressionCodecClass - (None by default)

Save this RDD as a SequenceFile of serialized objects. The serializer used is pyspark.serializers.PickleSerializer, default batch size is 10.

>>> tmpFile = NamedTemporaryFile(delete=True)
>>> tmpFile.close()
>>> sc.parallelize([1, 2, 'spark', 'rdd']).saveAsPickleFile(tmpFile.name, 3)
>>> sorted(sc.pickleFile(tmpFile.name, 5).collect())
[1, 2, 'rdd', 'spark']

Save this RDD as a text file, using string representations of elements.

>>> tempFile = NamedTemporaryFile(delete=True)
>>> tempFile.close()
>>> sc.parallelize(range(10)).saveAsTextFile(tempFile.name)
>>> from fileinput import input
>>> from glob import glob
>>> ''.join(sorted(input(glob(tempFile.name + "/part-0000*"))))
'0\n1\n2\n3\n4\n5\n6\n7\n8\n9\n'

Empty lines are tolerated when saving to text files.

>>> tempFile2 = NamedTemporaryFile(delete=True)
>>> tempFile2.close()
>>> sc.parallelize(['', 'foo', '', 'bar', '']).saveAsTextFile(tempFile2.name)
>>> ''.join(sorted(input(glob(tempFile2.name + "/part-0000*"))))
'\n\n\nbar\nfoo\n'

Return the key-value pairs in this RDD to the master as a dictionary.

>>> m = sc.parallelize([(1, 2), (3, 4)]).collectAsMap()
>>> m[1]
2
>>> m[3]
4

Return an RDD with the keys of each tuple.

>>> m = sc.parallelize([(1, 2), (3, 4)]).keys()
>>> m.collect()
[1, 3]

Return an RDD with the values of each tuple.

>>> m = sc.parallelize([(1, 2), (3, 4)]).values()
>>> m.collect()
[2, 4]

Merge the values for each key using an associative reduce function.

This will also perform the merging locally on each mapper before sending results to a reducer, similarly to a "combiner" in MapReduce.

Output will be hash-partitioned with numPartitions partitions, or the default parallelism level if numPartitions is not specified.

>>> from operator import add
>>> rdd = sc.parallelize([("a", 1), ("b", 1), ("a", 1)])
>>> sorted(rdd.reduceByKey(add).collect())
[('a', 2), ('b', 1)]

Merge the values for each key using an associative reduce function, but return the results immediately to the master as a dictionary.

This will also perform the merging locally on each mapper before sending results to a reducer, similarly to a "combiner" in MapReduce.

>>> from operator import add
>>> rdd = sc.parallelize([("a", 1), ("b", 1), ("a", 1)])
>>> sorted(rdd.reduceByKeyLocally(add).items())
[('a', 2), ('b', 1)]

Count the number of elements for each key, and return the result to the master as a dictionary.

>>> rdd = sc.parallelize([("a", 1), ("b", 1), ("a", 1)])
>>> sorted(rdd.countByKey().items())
[('a', 2), ('b', 1)]

Return an RDD containing all pairs of elements with matching keys in self and other.

Each pair of elements will be returned as a (k, (v1, v2)) tuple, where (k, v1) is in self and (k, v2) is in other.

Performs a hash join across the cluster.

>>> x = sc.parallelize([("a", 1), ("b", 4)])
>>> y = sc.parallelize([("a", 2), ("a", 3)])
>>> sorted(x.join(y).collect())
[('a', (1, 2)), ('a', (1, 3))]

Perform a left outer join of self and other.

For each element (k, v) in self, the resulting RDD will either contain all pairs (k, (v, w)) for w in other, or the pair (k, (v, None)) if no elements in other have key k.

Hash-partitions the resulting RDD into the given number of partitions.

>>> x = sc.parallelize([("a", 1), ("b", 4)])
>>> y = sc.parallelize([("a", 2)])
>>> sorted(x.leftOuterJoin(y).collect())
[('a', (1, 2)), ('b', (4, None))]

Perform a right outer join of self and other.

For each element (k, w) in other, the resulting RDD will either contain all pairs (k, (v, w)) for v in this, or the pair (k, (None, w)) if no elements in self have key k.

Hash-partitions the resulting RDD into the given number of partitions.

>>> x = sc.parallelize([("a", 1), ("b", 4)])
>>> y = sc.parallelize([("a", 2)])
>>> sorted(y.rightOuterJoin(x).collect())
[('a', (2, 1)), ('b', (None, 4))]

Return a copy of the RDD partitioned using the specified partitioner.

>>> pairs = sc.parallelize([1, 2, 3, 4, 2, 4, 1]).map(lambda x: (x, x))
>>> sets = pairs.partitionBy(2).glom().collect()
>>> set(sets[0]).intersection(set(sets[1]))
set([])

Generic function to combine the elements for each key using a custom set of aggregation functions.

Turns an RDD[(K, V)] into a result of type RDD[(K, C)], for a "combined type" C. Note that V and C can be different -- for example, one might group an RDD of type (Int, Int) into an RDD of type (Int, List[Int]).

Users provide three functions:

• createCombiner, which turns a V into a C (e.g., creates a one-element list)
• mergeValue, to merge a V into a C (e.g., adds it to the end of a list)
• mergeCombiners, to combine two C's into a single one.

In addition, users can control the partitioning of the output RDD.

>>> x = sc.parallelize([("a", 1), ("b", 1), ("a", 1)])
>>> def f(x): return x
>>> def add(a, b): return a + str(b)
>>> sorted(x.combineByKey(str, add, add).collect())
[('a', '11'), ('b', '1')]

Aggregate the values of each key, using given combine functions and a neutral "zero value". This function can return a different result type, U, than the type of the values in this RDD, V. Thus, we need one operation for merging a V into a U and one operation for merging two U's, The former operation is used for merging values within a partition, and the latter is used for merging values between partitions. To avoid memory allocation, both of these functions are allowed to modify and return their first argument instead of creating a new U.

Merge the values for each key using an associative function "func" and a neutral "zeroValue" which may be added to the result an arbitrary number of times, and must not change the result (e.g., 0 for addition, or 1 for multiplication.).

>>> rdd = sc.parallelize([("a", 1), ("b", 1), ("a", 1)])
>>> from operator import add
>>> rdd.foldByKey(0, add).collect()
[('a', 2), ('b', 1)]

Group the values for each key in the RDD into a single sequence. Hash-partitions the resulting RDD with into numPartitions partitions.

Note: If you are grouping in order to perform an aggregation (such as a sum or average) over each key, using reduceByKey will provide much better performance.

>>> x = sc.parallelize([("a", 1), ("b", 1), ("a", 1)])
>>> map((lambda (x,y): (x, list(y))), sorted(x.groupByKey().collect()))
[('a', [1, 1]), ('b', [1])]

Pass each value in the key-value pair RDD through a flatMap function without changing the keys; this also retains the original RDD's partitioning.

>>> x = sc.parallelize([("a", ["x", "y", "z"]), ("b", ["p", "r"])])
>>> def f(x): return x
>>> x.flatMapValues(f).collect()
[('a', 'x'), ('a', 'y'), ('a', 'z'), ('b', 'p'), ('b', 'r')]

Pass each value in the key-value pair RDD through a map function without changing the keys; this also retains the original RDD's partitioning.

>>> x = sc.parallelize([("a", ["apple", "banana", "lemon"]), ("b", ["grapes"])])
>>> def f(x): return len(x)
>>> x.mapValues(f).collect()
[('a', 3), ('b', 1)]

Alias for cogroup but with support for multiple RDDs.

>>> w = sc.parallelize([("a", 5), ("b", 6)])
>>> x = sc.parallelize([("a", 1), ("b", 4)])
>>> y = sc.parallelize([("a", 2)])
>>> z = sc.parallelize([("b", 42)])
>>> map((lambda (x,y): (x, (list(y[0]), list(y[1]), list(y[2]), list(y[3])))),                 sorted(list(w.groupWith(x, y, z).collect())))
[('a', ([5], [1], [2], [])), ('b', ([6], [4], [], [42]))]

For each key k in self or other, return a resulting RDD that contains a tuple with the list of values for that key in self as well as other.

>>> x = sc.parallelize([("a", 1), ("b", 4)])
>>> y = sc.parallelize([("a", 2)])
>>> map((lambda (x,y): (x, (list(y[0]), list(y[1])))), sorted(list(x.cogroup(y).collect())))
[('a', ([1], [2])), ('b', ([4], []))]

Return a subset of this RDD sampled by key (via stratified sampling). Create a sample of this RDD using variable sampling rates for different keys as specified by fractions, a key to sampling rate map.

>>> fractions = {"a": 0.2, "b": 0.1}
>>> rdd = sc.parallelize(fractions.keys()).cartesian(sc.parallelize(range(0, 1000)))
>>> sample = dict(rdd.sampleByKey(False, fractions, 2).groupByKey().collect())
>>> 100 < len(sample["a"]) < 300 and 50 < len(sample["b"]) < 150
True
>>> max(sample["a"]) <= 999 and min(sample["a"]) >= 0
True
>>> max(sample["b"]) <= 999 and min(sample["b"]) >= 0
True

Return each (key, value) pair in self that has no pair with matching key in other.

>>> x = sc.parallelize([("a", 1), ("b", 4), ("b", 5), ("a", 2)])
>>> y = sc.parallelize([("a", 3), ("c", None)])
>>> sorted(x.subtractByKey(y).collect())
[('b', 4), ('b', 5)]

Return each value in self that is not contained in other.

>>> x = sc.parallelize([("a", 1), ("b", 4), ("b", 5), ("a", 3)])
>>> y = sc.parallelize([("a", 3), ("c", None)])
>>> sorted(x.subtract(y).collect())
[('a', 1), ('b', 4), ('b', 5)]

Creates tuples of the elements in this RDD by applying f.

>>> x = sc.parallelize(range(0,3)).keyBy(lambda x: x*x)
>>> y = sc.parallelize(zip(range(0,5), range(0,5)))
>>> map((lambda (x,y): (x, (list(y[0]), (list(y[1]))))), sorted(x.cogroup(y).collect()))
[(0, ([0], [0])), (1, ([1], [1])), (2, ([], [2])), (3, ([], [3])), (4, ([2], [4]))]

Return a new RDD that has exactly numPartitions partitions.

Can increase or decrease the level of parallelism in this RDD. Internally, this uses a shuffle to redistribute data. If you are decreasing the number of partitions in this RDD, consider using `coalesce`, which can avoid performing a shuffle.

>>> rdd = sc.parallelize([1,2,3,4,5,6,7], 4)
>>> sorted(rdd.glom().collect())
[[1], [2, 3], [4, 5], [6, 7]]
>>> len(rdd.repartition(2).glom().collect())
2
>>> len(rdd.repartition(10).glom().collect())
10

Return a new RDD that is reduced into `numPartitions` partitions.

>>> sc.parallelize([1, 2, 3, 4, 5], 3).glom().collect()
[[1], [2, 3], [4, 5]]
>>> sc.parallelize([1, 2, 3, 4, 5], 3).coalesce(1).glom().collect()
[[1, 2, 3, 4, 5]]

Zips this RDD with another one, returning key-value pairs with the first element in each RDD second element in each RDD, etc. Assumes that the two RDDs have the same number of partitions and the same number of elements in each partition (e.g. one was made through a map on the other).

>>> x = sc.parallelize(range(0,5))
>>> y = sc.parallelize(range(1000, 1005))
>>> x.zip(y).collect()
[(0, 1000), (1, 1001), (2, 1002), (3, 1003), (4, 1004)]

Zips this RDD with its element indices.

The ordering is first based on the partition index and then the ordering of items within each partition. So the first item in the first partition gets index 0, and the last item in the last partition receives the largest index.

This method needs to trigger a spark job when this RDD contains more than one partitions.

>>> sc.parallelize(["a", "b", "c", "d"], 3).zipWithIndex().collect()
[('a', 0), ('b', 1), ('c', 2), ('d', 3)]

Zips this RDD with generated unique Long ids.

Items in the kth partition will get ids k, n+k, 2*n+k, ..., where n is the number of partitions. So there may exist gaps, but this method won't trigger a spark job, which is different from zipWithIndex

>>> sc.parallelize(["a", "b", "c", "d", "e"], 3).zipWithUniqueId().collect()
[('a', 0), ('b', 1), ('c', 4), ('d', 2), ('e', 5)]

Assign a name to this RDD.

>>> rdd1 = sc.parallelize([1,2])
>>> rdd1.setName('RDD1')
>>> rdd1.name()
'RDD1'

Get the RDD's current storage level.

>>> rdd1 = sc.parallelize([1,2])
>>> rdd1.getStorageLevel()
StorageLevel(False, False, False, False, 1)
>>> print(rdd1.getStorageLevel())
Serialized 1x Replicated